Numerical problem based on Motion third law v² = u² + 2as

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of -0.5 m/s². How much distance will be covered by the scooter before it stops?

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Solution.
(v² = u² + 2as)
where v is velocity or speed, u is initial velocity, a is accceleration and s is distance

Initial speed, u= 10 m/s
Final speed, v=0 (Scooter stops)
Acceleration, a=-0.5 m/s²
And, Distance covered, s = ? (To be calculated)

Now, putting these values in the third equation of motion :

We get:

(0)² = (10)² +2 x (-0.5) x s
0 = 10 x 10 + (-1) x s
0 = 100 + (-1s)

So we can write it as-

1s = 100
s=100/1
So "s" =100 m

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